Source: cirosantilli/polynomial-over-a-commutative-ring

= Polynomial over a commutative ring
{wiki}

Unlike <Polynomial over a ring>[over non-commutative rings], polynomials do look like proper <polynomials> over <commutative ring>.

In particular, <Hilbert's tenth problem> is about <polynomials> over the <integers>, which is a <commutative ring>, and therefore brings mindshare to this definition.

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