Allyl bromide
= Allyl bromide
The compound $\mathrm{CH_2{=}CHCH_2Br}$. <nucleophilic substitution> at its bromomethylene <carbon> introduces an <allyl group> without consuming the <alkene>.
= Allyl bromide
The compound $\mathrm{CH_2{=}CHCH_2Br}$. <nucleophilic substitution> at its bromomethylene <carbon> introduces an <allyl group> without consuming the <alkene>.