Past exam of the chemistry A course of the University of Cambridge 2021 Paper 1 A4 a v Solution 2026-10-20
The hydrogen symmetry orbital mixes with both nitrogen and , giving three molecular orbitals. The two hydrogen functions mix with , giving a bonding pair and an antibonding pair. Eight valence electrons fill the lower levels asThis uses conventional numbering that reserves for the omitted nitrogen core orbital. The low and levels provide the principal N–H bonding molecular orbitals; the highest occupied level is the mainly nitrogen lone pair, with some bonding admixture permitted by the pyramidal geometry. Empty and levels are antibonding. Symmetry fixes which orbitals can mix, rather than their quantitative energy separations.
Original qualitative ammonia molecular orbital diagram comparing pyramidal and planar geometries; the core orbital is omitted
. Details. Past exam of the chemistry A course of the University of Cambridge 2021 Paper 1 A4 b ii Solution 2026-10-20
For planar ammonia, the nitrogen valence atomic orbitals have symmetries , and . The hydrogen symmetry orbitals span . Consequently the in-plane orbitals form a bonding orbital, a bonding pair and their antibonding partners. The out-of-plane has no matching hydrogen combination and remains a nonbonding orbital. With the core omitted, the conventional valence occupation isThe preceding ammonia molecular orbital diagram shows the correlation. On pyramidalization, and both correlate with of the C3v point group, permitting s–p orbital mixing. The pure planar lone pair can acquire bonding character, lowering its energy and helping stabilize the pyramid. Symmetry alone does not provide a numerical inversion barrier.[ref]
