= Angular interference integral for two point scatterers
{title2=$\int e^{ik\hat{\mathbf r}\cdot\mathbf d}d\Omega=4\pi\sin(kd)/(kd)$}
Taking the polar axis along the separation vector reduces the solid-angle <integral> to $2\pi\int_{-1}^1e^{ikdu}du$. Thus the total <scattering cross-section> contains the <interference> term $2\operatorname{Re}(c_1c_2^*)\sin(kd)/(kd)$ as well as the two self terms. This is an outgoing-angle <integral> for fixed incident direction, rather than an average over the incoming beam.
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