= Bracket trace on the three-strand Temperley-Lieb algebra
{title2=$\operatorname{tr}(1)=\delta^2,\quad\operatorname{tr}(e_i)=\delta,\quad\operatorname{tr}(e_1e_2)=1$}
Close a three-strand planar <tangle> and evaluate its reduced <Kauffman bracket>. The basis $1,e_1,e_2,e_1e_2,e_2e_1$ has the displayed trace values, with the last value also valid for $e_2e_1$. Writing braid generators as $A1+A^{-1}e_i$ turns knot-polynomial computations into a five-dimensional algebra calculation.
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