Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 4 7A b Solution Created 2026-09-24 Updated 2026-10-03
Start with the germ selected in part (a) and continue it along paths in . At the two branch points,The monodromy reflection at a square-root branch point therefore shows that continuation once around sends to , while continuation once around sends it to . Composing these reflections produces every translation by an even multiple of . Hence the branches of the complex inverse sine are
Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 13E a iii Solution Created 2026-09-24 Updated 2026-09-25
Every path can change sheets only by applying the two reflectionsTheir products satisfyThus an even number of reflections gives a translation by an integral multiple of , while an odd number gives a translated reflection. All possible values are thereforein agreement with the branches of the complex inverse sine.