Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 138 3 b Solution Created 2026-10-03 Updated 2026-10-05
There is a missing hypothesis in the original PDF: must be a splitting field for finite group representations. For example,because and the quadratic factor is irreducible. This algebra has two simple modules, whereas has three conjugacy classes, all -regular. Thus the printed assertion for an arbitrary field is false.
Under the intended splitting hypothesis, fix compatible lifts defining Brauer characters. Let be the set of conjugacy classes of p-regular elements. Character additivity and the tensor-product formula define the unital algebra homomorphismWe use the Brauer character basis theorem: over a splitting field the irreducible Brauer characters form a complex basis of the class functions on the p-regular conjugacy classes. Therefore maps the basis bijectively to a basis and is an algebra isomorphism. Comparing dimensions givesIsomorphism classes are understood in the count.