BRST-closed operator
= BRST-closed operator
{c}
A BRST-closed operator $O$ satisfies $QO=0$. It represents a physical observable when it is not also BRST exact.
= BRST-closed operator
{c}
A BRST-closed operator $O$ satisfies $QO=0$. It represents a physical observable when it is not also BRST exact.