Canonical commutation relation
= Canonical commutation relation
{wiki}
In position representation, $x$ acts by multiplication and $p_x=-i\hbar\partial_x$, so
$$
[x,p_x]=i\hbar I.
$$
= Canonical commutation relation
{wiki}
In position representation, $x$ acts by multiplication and $p_x=-i\hbar\partial_x$, so
$$
[x,p_x]=i\hbar I.
$$