Chiral superfield constrained by a nilpotent superfield
= Chiral superfield constrained by a nilpotent superfield
{title2=$XY=0$}
With $X^2=0$ and invertible $F_X$, the additional <chiral superfield> $Y=y+\sqrt2\theta\chi+\theta^2F_Y$ satisfying $XY=0$ has $y=(G\chi)/F_X-(GG)F_Y/(2F_X^2)$. Its <Weyl spinor> $\chi$ and <auxiliary field> $F_Y$ remain independent. This eliminates the independent scalar. It does not force $Y^2=0$.