Coalgebra for a comonad 2026-10-06
Cofree coalgebra 2026-10-06
For a comonad, the cofree coalgebra on is . A map transposes to the coalgebra morphism . This gives the adjunction with the forgetful functor.
Coreflective subcategory 2026-10-06
A full subcategory is coreflective when its inclusion has a right adjoint . The counit is universal for maps to from objects of the subcategory. The comonad is idempotent. For a finite-limit-closed coreflective subcategory of a topos, its coalgebra construction can prove that the subcategory is itself a topos.
Exponentials in a coalgebra topos 2026-10-06
For a finite-limit-preserving comonad on a topos, start with the cofree coalgebra on the ambient exponential . Its underlying evaluation is . Transpose the two expressions and first using the ambient exponential and then the cofree adjunction. Their coalgebra equalizer represents exactly the maps whose evaluations respect coalgebra structure. Thus coalgebra exponentials need not be the underlying ambient exponentials.
Idempotent comonad 2026-10-06
A comonad is idempotent when its comultiplication is invertible. Its coalgebra category identifies with the coreflective subcategory of objects on which the counit is invertible. A coreflective inclusion produces such a comonad.
Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 20 1 i Solution Created 2026-10-03 Updated 2026-10-06
Write the comonad as and its category of coalgebras for a comonad as . A coalgebra for a comonad is a map with and . A morphism satisfies . Let be the forgetful functor and let be the cofree coalgebra. The adjunction has the explicit correspondenceWe construct the three pieces of the elementary topos structure.
Because preserves finite limits, each underlying finite limiting cone has a unique coalgebra structure induced by the structures on its vertices. The counit and coassociativity equations can be checked after its jointly monic projections. Thus creates finite limits and reflects isomorphisms. A morphism of coalgebras is monic exactly when its underlying morphism is monic, by the diagonal criterion using the created pullback.
For exponentials in a coalgebra topos, fix coalgebras and and put in . On the cofree coalgebra there is an underlying evaluationThe two mapsuse in the second expression. Transpose them in to maps , and then transpose across to coalgebra morphisms . Take their equalizer in .
An underlying map corresponds to a coalgebra map . The equation saying that the original map is a coalgebra morphism is precisely , since for the structure . By the cofree adjunction, this is equivalent to , hence to unique factorization through . Thereforenaturally in . This constructs the required exponential object.
For the subobject classifier of a coalgebra topos, let be the underlying subobject classifier, and let classify the mono . Its cofree transpose is the coalgebra endomorphismDefine as the equalizer of and . The transpose of factors through this equalizer and gives .
Indeed, for a subobject classified by , the pullback has characteristic map . It is always contained in , by naturality of the counit. Equality holds exactly when restricts to a coalgebra structure on ; its axioms then follow by composing with the monomorphisms and . Under , the classifying map becomes . The equality of subobjects is . Transposing this equality gives , so exactly the coalgebra subobjects correspond to maps . Their pullback of is the desired subcoalgebra, and uniqueness follows from uniqueness of .
Thus we have finite limits, exponentials and a subobject classifier:The construction does not assume that preserves the underlying exponentials or underlying subobject classifier.