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 Incoming links: Convolution of a Cauchy distribution and a uniform distribution

Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2019 / Paper 2 / 14 / d / ii / Solution 2026-10-18
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Insert the two densities into the convolution of probability densities:
h(z)=π1​∫−1/21/2​1+(z−y)2dy​.
(1)
Using the antiderivative −arctan(z−y) with respect to y gives
h(z)=πarctan(z+1/2)−arctan(z−1/2)​​,z∈R.
(2)
This is the convolution of a Cauchy distribution and a uniform distribution with half-width 1/2.
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