Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 111 3 c Solution Created 2026-09-24 Updated 2026-09-24
Suppose meets . Applying the homeomorphism shows that meets . If , choose one of its left descents. Part b places its image of in the corresponding negative half-space, while lies in the positive half-space. This is impossible, so . The unionis disjoint.
When is finite, the closures are the simplicial chambers cut out by the reflecting hyperplanes. Intersecting them with a sphere centred at the origin gives simplices. A face of type has stabilizer the standard parabolic subgroup , so its translates are indexed by cosets , with reverse inclusion of cosets encoding incidence. This is precisely the Coxeter complex of .
Standard parabolic subgroup Created 2026-09-24 Updated 2026-09-24
For , the standard parabolic subgroup is . Its cosets index faces of a fixed type in the Coxeter complex.