= CP-conjugate decay-amplitude ratio
{c}
{title2=$\bar\lambda_{\bar f}=(p/q)A_{\bar f}/\bar A_{\bar f}$}
For $\lambda_f=(q/p)\bar A_f/A_f$, exchanging both initial <Flavor eigenstate>[flavour] and final-state labels defines $\bar\lambda_{\bar f}=(p/q)A_{\bar f}/\bar A_{\bar f}$. It equals $\lambda_f^{-1}$ exactly when $A_{\bar f}/\bar A_{\bar f}=A_f/\bar A_f$. This holds for a common <CP eigenstate> final ray. <CP symmetry> of paired amplitudes alone does not imply it for distinct final states: $p=q$, $A_f=\bar A_{\bar f}=2$, $\bar A_f=A_{\bar f}=1$ gives both ratios $1/2$.
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