Cubic oscillatory Gamma integral
= Cubic oscillatory Gamma integral
For $t>0$, contour rotation through angle $-\pi/6$ gives
$$
\int_0^\infty e^{-itu^3}du
=e^{-i\pi/6}t^{-1/3}\Gamma\left(\frac43\right).
$$
Taking real parts yields
$$
\int_0^\infty\cos(u^3)du
=\Gamma\left(\frac43\right)\cos\frac\pi6.
$$