Dawson function
= Dawson function
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{title2=$F_D(z)=e^{-z^2}\int_0^z e^{u^2}\,du$}
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= Dawson integral
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The Dawson function obeys $F_D'+2zF_D=1$ by <differentiation>. Its large-real-argument <asymptotic expansion> begins $F_D(z)=1/(2z)+1/(4z^3)+O(z^{-5})$. This inverse-power behavior contrasts with the separate exponentially growing factors in its definition.