de Sitter horizon temperature
= de Sitter horizon temperature
{c}
{title2=$T(r)=1/(2\pi R\sqrt{1-r^2/R^2})$}
In units $\hbar=c=k_B=1$, the central inertial observer has temperature $1/(2\pi R)$. The <Tolman temperature law> redshifts it to the displayed static-observer value. Its acceleration satisfies $4\pi^2T^2=a^2+R^{-2}$. Near the horizon the temperature approaches $a/(2\pi)$, as predicted by the <Unruh effect>; at the center temperature remains nonzero despite vanishing acceleration.