Degree of the derivative of an elliptic function
= Degree of the derivative of an elliptic function
{title2=$\deg g'$}
If an elliptic function $g$ has degree $d$ and $r$ distinct poles in a fundamental parallelogram, then each pole order increases by one under differentiation, so
$$
\deg g'=d+r.
$$
Because $1\leq r\leq d$, this gives $d+1\leq\deg g'\leq2d$.