Delta method
= Delta method
{wiki}
If $\sqrt n(T_n-\theta)$ is asymptotically normal, differentiability gives $\sqrt n(g(T_n)-g(\theta))$ the variance multiplied by $g'(\theta)^2$.
= Delta method
{wiki}
If $\sqrt n(T_n-\theta)$ is asymptotically normal, differentiability gives $\sqrt n(g(T_n)-g(\theta))$ the variance multiplied by $g'(\theta)^2$.