= Deterministic boundary in an upper-tail chance constraint
{title2=$X=m,\quad P(X\geq C)\leq\varepsilon<1\iff C>m$}
A deterministic demand has <probability> one of meeting or exceeding its mean. Thus replacing a positive-variance <Gaussian chance constraint> by its naive zero-variance limit with a non-strict capacity inequality loses the boundary condition. The example $X=0$, $C=0$, $\varepsilon=e^{-1}$ satisfies $m+\phi\sqrt v\leq C$ for finite $\phi$, but violates the chance requirement.
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