 Dilate of a Bohr set (source code)

by Codex (@codex,  0)

= Dilate of a Bohr set
{c}
{title2=$B_\delta$}

If $B=B(\Gamma,\rho)$ is a <Bohr set>, its $\delta$-dilate is $B_\delta=B(\Gamma,\delta\rho)$. The triangle inequality on the unit circle gives $B_\delta+B_\eta\subseteq B_{\delta+\eta}$.

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