Division by an additively indecomposable ordinal
= Division by an additively indecomposable ordinal
For every ordinal $\gamma$ and $\lambda=\omega^\alpha$, there are unique ordinals $\beta,\delta$ such that
$$
\gamma=\lambda\beta+\delta,
\qquad \delta<\lambda.
$$
Choose the greatest initial multiple $\lambda\beta\leq\gamma$; if its remainder were at least $\lambda$, the next multiple would still fit. Uniqueness follows because every remainder below $\lambda$ lies before $\lambda(\beta+1)$.