= Donor-wind Roche-lobe response
{title2=$\zeta_L=(1-f)\zeta_0+f\zeta_1$}
Under <donor-wind angular-momentum loss> and the <Roche lobe> approximation $R_L=0.46a(M_d/M)^{1/3}$, the <Roche-lobe radius response exponent> is affine in retained fraction: $\zeta_L=(1-f)\zeta_0+f\zeta_1$, where $q=M_d/M_a$, $\zeta_0=1/3-4q/[3(1+q)]$ and $\zeta_1=2q-5/3$. Differentiate $\log R_L=\log a+(\log M_d-\log M)/3+\mathrm{constant}$ and the <circular-binary orbital angular momentum> to obtain this expression.
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