Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 55 3 d Created 2026-10-03 Updated 2026-10-06
The chosen opacity law makes spatially constant. This closes the Eddington standard model relation between its radiation-pressure and total-pressure gradients. The four roman-numbered proofs use the whole model, not only this opacity assumption.
Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 55 3 i Solution 2026-10-06
Divide the radiation-pressure gradient by the total-pressure gradient. Radiative diffusion in a star and hydrostatic equilibrium giveThis last quantity is independent of radius under the specified opacity assumption. Integration gives . With the standard idealized zero-pressure outer boundary, where both components vanish, . The stellar gas-pressure fraction is thereforeconstant throughout the model. This is the Eddington standard model idealization. A finite photospheric pressure offset would need its boundary treatment; the differential relation alone does not set the integration constant to zero.
Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 317 4 ii Solution 2026-09-28
The radiative-pressure equation isDividing by hydrostatic equilibrium and substituting
givesa constant. Since both pressures vanish at the surface,
and is constant throughout the star. Part i therefore haswith spatially constant .
givesa constant. Since both pressures vanish at the surface,
and is constant throughout the star. Part i therefore haswith spatially constant .
Writing andgives the Lane-Emden equationThe surface is the first zero . The equation has no elementary closed-form solution; among nonnegative indices, the standard analytic cases are . This Eddington standard model approximates chemically homogeneous massive main-sequence stars with substantial radiation pressure.