Choose the rational point and the coherent sheaf supported there. By skyscraper sheaf cohomology, .
Its dual of a sheaf is zero. Away from its source is zero. At , a homomorphism must send one to an element annihilated by the maximal ideal. Since , that ideal contains a nonzero coordinate parameter; the local ring is an integral domain, so the image must vanish. This proves that every local homomorphism vanishes. Consequently
There is no contradiction with Serre duality: the ordinary sheaf dual suffices for locally free sheaves, but general coherent sheaves require an Ext functor. This example illustrates failure of ordinary sheaf-dual Serre duality for a skyscraper sheaf.