Fermi superfield
= Fermi superfield
A Fermi superfield $\Lambda_-^a$ obeys $\bar D_+\Lambda_-^a=f_a(\Phi)$. A supersymmetric $J$-type coupling $\int d\theta^+\Lambda_-^aJ^a(\Phi)$ requires $\sum_af_aJ^a=0$.
= Fermi superfield
A Fermi superfield $\Lambda_-^a$ obeys $\bar D_+\Lambda_-^a=f_a(\Phi)$. A supersymmetric $J$-type coupling $\int d\theta^+\Lambda_-^aJ^a(\Phi)$ requires $\sum_af_aJ^a=0$.