Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 107 4 b iii Solution Created 2026-09-24 Updated 2026-09-25
Suppose a nonzero solution did not change sign. Replacing it by if necessary gives . The argument of part (b.ii) is local and invariant under translation and scaling: it applies on every ball whose concentric double lies in . If the zero set of had positive measure, a density point and this local result would make vanish on one ball. Applying the same result successively on overlapping balls would then give throughout the connected ball , a contradiction. Thus the zero set has measure zero in . Applying part (a.i) to givesfor every compactly supported function ; the omitted zero set has measure zero. But , while the variational characterization of the First Dirichlet eigenvalue provides a withThis contradiction proves that every nonzero solution takes both positive and negative values.