Fourier transform of an interval indicator
= Fourier transform of an interval indicator
For $f=\mathbf1_{[-a,a]}$ and the convention $\widehat f(\xi)=\int f(x)e^{-ix\xi}\,dx$,
$$
\widehat f(\xi)=\frac{2\sin(a\xi)}{\xi},
$$
with its continuous value $2a$ at zero.