Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 2 3 i Solution Created 2026-10-03 Updated 2026-10-14
Suppose has a finite group presentation. Work in the free product and putThe freely generate a subgroup of . Indeed, in a reduced word in these conjugates, combine adjacent powers with the same index. Expanding the remaining word leaves nonzero powers of separated by nonzero powers of , so the normal form theorem for a free product makes it nonidentity. This proves the free conjugate bases in a rank-two free group fact we need.
The group homomorphism killing sends to , including . These are a free conjugate basis by the same argument with interchanged. A nonempty reduced word in the therefore has nontrivial image and cannot be trivial in . Thus extends to an isomorphism between the two rank- free groups embedded in .
Adjoin one stable letter implementing this isomorphism:We assume Britton's lemma, including its assertion that the base embeds in this HNN extension, and the factor-embedding assertion of the normal form theorem for a free product. Hence . The presentation is finite, and its relations express every generator in :Eliminating by Tietze transformations therefore gives a two-generator finite presentation with . This explicitly constructs the two-generator HNN embedding; it does not rely on an arbitrary two-generator embedding preserving finite presentability.
Two-generator HNN embedding 2026-10-14
For , put , , , and for . The freely generate by free conjugate bases in a rank-two free group. The do too: projection killing maps them to a free conjugate basis, so no reduced word in them is trivial. The HNN extension adjoining embeds by Britton's lemma. Since and , its generators reduce to . For finitely many and this is a finite group presentation; for effective countably many generators and enumerable it is a two-generator recursive presentation of a group.