= Gaussian effective bandwidth
{c}
{title2=$\alpha(s)=\lambda+\sigma^2s/2$}
For a <normal distribution> $N(\lambda,\sigma^2)$, the logarithm of its <moment-generating function> is $s\lambda+s^2\sigma^2/2$. Dividing by $s>0$ gives its <effective bandwidth>. Independent demands add these bandwidths. For total mean $m$ and positive total <variance> $v$, optimizing a <Chernoff bound> with target $e^{-\gamma}$, $\gamma>0$, yields the sufficient margin $C\geq m+\sqrt{2\gamma v}$.
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