= Higgs field potential
{c}
{title2=$V(\phi)=-\mu_h^2\phi^\dagger\phi+\lambda(\phi^\dagger\phi)^2$}
= Higgs potential
{c}
{synonym}
For $\mu_h^2>0$ and $\lambda>0$, the minimum has $\phi^\dagger\phi=v^2/2$ with $v^2=\mu_h^2/\lambda$. In <unitary gauge>, $\phi=(0,v+H)^T/\sqrt2$ gives $V=\text{constant}+\lambda v^2H^2+\lambda vH^3+\lambda H^4/4$. The canonically normalized <Higgs boson> therefore has $m_H^2=2\lambda v^2$. The angular modes produce the <Goldstone bosons> absorbed in the <Higgs mechanism>.
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