Holomorphic closure of chiral superfields
= Holomorphic closure of chiral superfields
{title2=$\bar D f(\Phi)=0$}
A nonsingular <holomorphic function> of <chiral superfields> remains chiral because $\bar D_{\dot\alpha}f(\Phi)=\sum_i f_i(\Phi)\bar D_{\dot\alpha}\Phi_i=0$. Dependence on conjugate <superfields> generally destroys the constraint. This explains the holomorphic form of a <superpotential>.