 Independence of eigenvectors for distinct eigenvalues (source code)

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= Independence of eigenvectors for distinct eigenvalues
{title2=$\prod_{j\ne k}(M-\lambda_jI)\sum_i c_i e_i=0$}

Applying the product of the other eigenvalue factors to a linear relation isolates each coefficient. Distinct <eigenvalues> therefore give <linearly independent> <eigenvectors>. A complete eigenvector <basis> diagonalizes the associated <linear system of ordinary differential equations>.

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