Inverse of an axis-angle linear map
= Inverse of an axis-angle linear map
Invert the axial scalar and invert the perpendicular complex scalar $\alpha+i\gamma$ as $(\alpha-i\gamma)/(\alpha^2+\gamma^2)$.
= Inverse of an axis-angle linear map
Invert the axial scalar and invert the perpendicular complex scalar $\alpha+i\gamma$ as $(\alpha-i\gamma)/(\alpha^2+\gamma^2)$.