Inverse-square potential
= Inverse-square potential
{title2=$V(r)=-k/r$}
The potential $V(r)=-k/r$ generates the attractive inverse-square <central force> $F=-k r/r^3$.
= Inverse-square potential
{title2=$V(r)=-k/r$}
The potential $V(r)=-k/r$ generates the attractive inverse-square <central force> $F=-k r/r^3$.