Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 84 4 a Solution Created 2026-10-03 Updated 2026-10-14
The K-epsilon turbulence model evolves turbulent kinetic energy and its turbulent kinetic energy dissipation rate , rather than resolving turbulent fluctuations. It closes the Reynolds stress with an isotropic eddy viscosity, , and models transport of and by gradient diffusion with coefficients and . Production is tied to mean strain; dissipation-equation production and destruction are modeled terms with empirical constants. The characteristic velocity and length are and . These assumptions are primarily for high Reynolds number, and strongly anisotropic flow, sharp interfaces and molecular-viscosity-dominated regions need additional treatment. The dissipation equation is a closure, not a second exact energy-conservation law.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 73 3 i Solution Created 2026-10-03 Updated 2026-10-14
Here is turbulent kinetic energy per unit mass, , rather than the permeability of a porous medium used in the porous-flow questions. The K-epsilon turbulence model represents the high-Reynolds-number transport of this energy and its turbulent kinetic energy dissipation rate .
In the equation, is the divergence of modeled turbulent diffusion, is mean-shear production, and is molecular conversion of fluctuation energy into heat. Statistical stationarity and fully developed flow have removed storage and streamwise advection from this reduction.
In the equation, transports dissipation intensity; models its generation associated with energy production; and models its destruction. The time scale supplies the source-rate dimension. The equation is a closure, not another energy-conservation equation. Finally, has dynamic viscosity dimensions and parametrizes Reynolds stress transport; set the relative diffusion strengths, and the remaining constants calibrate the closure.