= Laminar Ekman boundary stress
{title2=$T_b=\rho\sqrt{f\nu/2}(1+i)W_g$}
For $f>0$, a stationary lower <no-slip boundary condition> below uniform exterior <geostrophic flow> $W_g$ produces $W_E=-W_g e^{-(1+i)z/\delta_E}$. The upward shear component at the bottom is $T_b=\rho\nu W_E^{\prime}(0)=\rho\sqrt{f\nu/2}(1+i)W_g$; the bottom traction on the fluid is $-T_b$. This law cannot be assigned to an arbitrary prescribed surface <wind stress> without an additional boundary condition.
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