= Linearly graded junction depletion width
{title2=$w=[12\varepsilon_s(V_b-V)/(e\alpha)]^{1/3}$}
Integrating the <electric field> across a <linearly graded p-n junction> gives $V_b-V=e\alpha w^3/(12\varepsilon_s)$, where positive $V$ means <forward bias>. Thus the <depletion region> width depends on the cube root of the remaining barrier voltage. Both the space-charge density and integration range grow with width; this differs from the square-root width law of an abrupt uniformly doped junction.
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