Liouville function
= Liouville function
{c}
{title2=$\lambda(n)$}
The Liouville function is $\lambda(n)=(-1)^{\Omega(n)}$, where $\Omega(n)$ is the <total number of prime factors> counted with multiplicity. It is a <completely multiplicative function>: multiplication adds prime-factor multiplicities, so $\lambda(ab)=\lambda(a)\lambda(b)$.