Mass per drag area
= Mass per drag area
{title2=$\mu=m/A_w$}
The <normalization> $\mu=m/A_w$ has units $\mathrm{kg\,m^{-2}}$. It converts the <Coriolis force> into a force per water-drag <area> and allows comparison with wind and <water> <stresses>. <Icebergs> generally have much larger $\mu$ than thin <ice floes>, but their effective air-to-water drag-area ratio also matters. A geometric depth becomes a <mass> per <area> only after multiplication by density.