Mean population of a Yule process (source code)

= Mean population of a Yule process
{title2=$\mathbb E X_t=e^{\lambda t}$}

For the Yule process starting from one individual, the generator applied to $f(n)=n$ gives
$$
\frac d{dt}\mathbb E X_t=\lambda\mathbb E X_t,
\qquad \mathbb E X_0=1,
$$
and hence $\mathbb E X_t=e^{\lambda t}$.