= Median rupture force under a linear ramp
{title2=$F_{1/2}=F_0\log[1+f\log2/(k_0F_0)]$}
Solving $p(F_{1/2})=1/2$ for <survival under a linear force ramp> gives the displayed expression. At large $f/(k_0F_0)$, its slope against $\log f$ approaches $F_0$; at low loading rate the <median> is approximately $f\log2/k_0$. A full fit can infer activation distance $k_BT/F_0$ and zero-force escape rate $k_0$. An absolute barrier additionally needs an attempt prefactor, and equilibrium binding strength additionally needs reverse-state information.
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