Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 70 6 ii Solution Created 2026-10-03 Updated 2026-10-14
Interpret the positive-distance assumption as disjoint compact enclosed bodies , certified for example by disjoint enclosing volumes. Merely having disjoint drawn control meshes is insufficient if one encloses the other or the meshes do not enclose their limit surfaces. For genuinely disjoint bodies, the closest pair lies on their boundaries: an interior point could move toward the other body and decrease the distance. Thus minimize over all pairs of limit-surface patches.
Use branch and bound on patch pairs. For regions , enclosing bounding volumes give a lower bound on their true minimum distance. For axis-aligned bounding boxes, compute this directly asAny pair of evaluated limit points provides a feasible upper bound; retain the smallest, . Start with a covering list of all coarse patch pairs. At each step, discard a pair when its lower bound is at least , otherwise refine the region with larger bounding diameter/error and enqueue its child pairs. Prefer the pair with smallest lower bound. Update with new feasible pairs; a local stationary-distance solve can improve it but cannot replace the global search.
Let be the minimum remaining lower bound, capped by if the list is empty. The current certificate isStop when . Compactness and shrinking valid patch enclosures ensure convergence to this tolerance under the interface assumptions. An equivalent mesh method must add each mesh's certified limit error; for Hausdorff distance errors , the separation error is at most . Finite mesh distance without such a bound is not the exact minimum distance between subdivision bodies.