Minimum Yarkovsky removal time
= Minimum Yarkovsky removal time
{title2=$D_0=\sqrt{C/B}$}
The law $t_y=BD+C/D$ for positive $B,C$ has a minimum at $D_0=\sqrt{C/B}$ with value $2\sqrt{BC}$. This size differs from the minimum of the ratio of removal and collision times.