Missing common-neighbour count in a binomial random graph
= Missing common-neighbour count in a binomial random graph
{title2=$\mathbb EX=\binom n2(1-p^2)^{n-2}$}
Let $X$ count unordered <vertex> pairs with no <common neighbour> in a <binomial random graph>. Each other <vertex> provides the required pair of <edges> independently, with success probability $p^2$. A fixed pair has no common neighbour with probability $(1-p^2)^{n-2}$. Summing its indicators gives the displayed <expectation>.