MOD3 binary divisibility problem
= MOD3 binary divisibility problem
{c}
{title2=$\{x:\operatorname{value}_2(x)\equiv0\pmod3\}$}
= MOD3
{c}
{synonym}
For a binary numeral, its remainder is the sum of its bits weighted alternately by $+1$ and $-1$ from the least significant position. A <balanced finite-monoid reduction circuit> adds these residues modulo three in two-bit encodings. A final zero test gives a uniform linear-size logarithmic-depth <Boolean circuit>, proving membership in <NC1>.