Brauer character basis theorem 2026-10-05
Over a splitting field for finite group representations of characteristic , the irreducible Brauer characters form a complex basis of the class functions on the p-regular elements. Independence is the character form of the Brauer–Nesbitt theorem. To obtain spanning, extend such a class function by zero on the p-singular classes. Ordinary irreducible characters form a basis of all class functions by character orthogonality. Restricting them to p-regular elements yields Brauer characters of reductions of an integral form of a group representation in a compatible splitting p-modular system; if needed, first extend scalars, which does not change the simple-module list under the splitting hypothesis. Each restriction is a nonnegative integral sum of simple Brauer characters by exact-sequence additivity and the Jordan–Hölder theorem. Thus these restrictions span, proving the assertion. Consequently the number of simple modules equals the number of p-regular conjugacy classes, and evaluation identifies the complexified modular representation ring with the product of one copy of for each such class.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 138 3 a Solution Created 2026-10-03 Updated 2026-10-05
The modular representation ring is the abelian group generated by isomorphism classes of finite-dimensional -modules, with relationsThe Jordan–Hölder theorem says that it is a free abelian group with basis the classes of the simple modules, and . To see independence, composition multiplicity for each fixed simple is an additive map to and reads off its basis coefficient.
Define , using the diagonal action in the tensor product of group representations. Tensoring over a field is exact in either argument, so multiplication respects the defining relations. Associativity and the symmetry give a commutative ring with identity , the trivial representation. Thus .
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 138 4 iv Solution Created 2026-10-03 Updated 2026-10-05
Completeness permits idempotent lifting from to . In particular, each projective cover lifts to a finite projective -lattice ; one can lift an idempotent presenting it as a summand of a finite free module. Set .
For a simple , every map factors through its simple head . Splitting and Schur lemma give . Exactness of this Hom functor along a composition series therefore givesPart (iii) identifies this with . By Maschke's theorem and splitting, is split semisimple, soThe reductions of any two integral forms of the same ordinary module have identical Brauer characters, hence identical composition multiplicities. We may thus reduce a direct-sum form for the displayed decomposition instead of . In the modular representation ring this givesComparing the simple basis coefficients proves , or .