Module of Kähler differentials
= Module of Kähler differentials
{c}
{title2=$\Omega_{B/A}$}
{wiki=Kähler_differential}
For a ring map $A\to B$, the module of Kähler differentials represents $A$-derivations: $\operatorname{Hom}_B(\Omega_{B/A},M)\cong\operatorname{Der}_A(B,M)$.