Moment of inertia of a uniform disc (source code)

= Moment of inertia of a uniform disc
{title2=$I=Ma^2/2$}

For a uniform disc of radius $a$ and mass $M$, annuli of radius $r$ and thickness $dr$ have mass $(M/\pi a^2)2\pi r\,dr$. Their axial <moment of inertia> sums to $I=\int_0^a r^2\,dm=Ma^2/2$.