Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 4 7A c Solution Created 2026-09-24 Updated 2026-10-03
Let the argument of increase by along a counterclockwise path enclosing both branch points. On a large circle, the branch chosen in part (a) satisfiesThe change in the primitive is consequentlyEquivalently, this is the composition of the two reflections described by the monodromy of the complex inverse sine. Thus, for this orientation,The reverse orientation gives . Both continued values invert the same , so on an open set of inverse values. The identity theorem extends this equality to every , proving the periodicity of the complex sine:
Periodicity of the complex sine 2026-10-03
The kernel of the complex exponential function givesThe same period appears as the translation generated by the monodromy of the complex inverse sine.